40w^2=5w

Solution for 40w^2=5w equation:

40w^2=5w

We move all terms to the left:

40w^2-(5w)=0

a = 40; b = -5; c = 0;
Δ = b2-4ac
Δ = -52-4·40·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5}{2*40}=\frac{0}{80}
=0
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5}{2*40}=\frac{10}{80}
=1/8
$